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2x^2-0.75=0
a = 2; b = 0; c = -0.75;
Δ = b2-4ac
Δ = 02-4·2·(-0.75)
Δ = 6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{6}}{2*2}=\frac{0-\sqrt{6}}{4} =-\frac{\sqrt{}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{6}}{2*2}=\frac{0+\sqrt{6}}{4} =\frac{\sqrt{}}{4} $
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